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Question

The products “A” and “B” formed in the below reactions are:


A
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B
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C
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D
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Solution

The correct option is A

The explanation for the correct option:

Option (A):

  1. According to the Saytzeff Rule, base-induced eliminations (E2) will primarily result in an olefin with a more strongly substituted double bond, implying that the product distribution will be governed by thermodynamics.
  2. Therefore, using the above rule of Saytzeff's, compound A is formed in the first reaction:
  3. Hofmann elimination is an amine elimination process that results in the formation of alkenes. The Hofmann product is generated, which is the least stable alkene (the one with the fewest substituents on the carbons of the double bond).
  4. Similarly, following the Hoffman elimination process, compound B is formed.

Final Answer: Therefore, option A is the correct option.


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