$0.001$ molal solution of $[P t {({N H}_{3})}_{4} {C l}_{4}]$ in water had a freezing point depression of $0.0054^{o} C$ . If $K_{f}$ for water is $1.80$ , the correct formula of the compound is :

[P t {({N H}_{3})}_{4} {C l}_{3}] C l

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[P t {({N H}_{3})}_{4} {C l}_{4}]

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[P t {({N H}_{3})}_{4} {C l}_{2}] {C l}_{2}

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[P t {({N H}_{3})}_{4} {C l}] {C l}_{3}

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Solution

The correct option is C $[P t {({N H}_{3})}_{4} {C l}_{2}] {C l}_{2}$
${Δ T}_{f} = i \times K_{f} \times$ molarity
$0.0054 = i \times 1.80 \times 0.001$
$\frac{0.0054}{1.80 \times 0.001} = i$
$i = 3$
For value of $i$ to be $3$ , the correct formula should be :-
$[P t {({N H}_{3})}_{4} {C l}_{2}] {C l}_{2}$

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Similar questions

Q. The correct name of

[P t {({N H}_{3})}_{4} {C l}_{2}] [P t {C l}_{4}]

is:

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} c l_{4}]

in water had a freezing point depression of

{0.0054}^{\circ}

. If

K_{f}

for water is 1.80, the correct formulation for the above molecule is

Q. Select the correct I.U.P.A.C name for

[P t (N H_{3})_{4}] [P t C l_{4}]

Q. The structure of

[P t (N H_{3})_{4}]^{2 +}

is ___________.

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

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0.001 molal solution of [Pt(NH3)4Cl4] in water had a freezing point depression of 0.0054oC. If Kf for water is 1.80, the correct formula of the compound is :

The correct option is C [Pt(NH3)4Cl2]Cl2ΔTf=i×Kf× molarity0.0054=i×1.80×0.0010.00541.80×0.001=ii=3For value of i to be 3, the correct formula should be :-[Pt(NH3)4Cl2]Cl2

$0.001$ molal solution of $[P t {({N H}_{3})}_{4} {C l}_{4}]$ in water had a freezing point depression of $0.0054^{o} C$ . If $K_{f}$ for water is $1.80$ , the correct formula of the compound is :