0-01 M solution of KCl and BaCl2 are prepared in water- The freezing point of KCl is found to be -2- C- What is the freezing point of BaCl2 to be completely ionised-

The correct option is A 3^∘ C T_f∝ i ∴ T_f for KCl T_f for BaCl_2 = i for KCli for BaCl_2 ∴ #160; T_f for KCl T_f for BaCl_2 = 23 (∵ T_fforKC ...

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Byju's Answer

Standard XII

Chemistry

Depression in Freezing Point

0.01 M soluti...

Question

$0.01 M$ solution of $K C l$ and $B a C l_{2}$ are prepared in water. The freezing point of $K C l$ is found to be $- 2^{\circ} C$ . What is the freezing point of $B a C l_{2}$ to be completely ionised?

- 3^{\circ} C

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+ 3^{\circ} C

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- 2^{\circ} C

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- 4^{\circ} C

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Solution

The correct option is A $- 3^{\circ} C$
$△ T_{f} \propto i$ $
$∴ \frac{△ T_{f} f o r K C l}{△ T_{f} f o r B a C l_{2}} = \frac{i f o r K C l}{i f o r B a C l_{2}}$
$∴ \frac{△ T_{f} f o r K C l}{△ T_{f} f o r B a C l_{2}} = \frac{2}{3} (∵ △ T_{f}$ for $K C l = 2)$
$∴ △ T_{f}$ for $B a C l_{2} = \frac{3 \times 2}{2} = 3$
$∴$ Freezing point of $B a C l_{2} = - 3^{\circ} C$

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0.01 M solution of KCl and BaCl2 are prepared in water. The freezing point of KCl is found to be −2∘C. What is the freezing point of BaCl2 to be completely ionised?

The correct option is A −3∘C△Tf∝i$∴△Tffor KCl△Tffor BaCl2=i for KCli for BaCl2∴△Tffor KCl△Tffor BaCl2=23(∵△Tf for KCl=2)∴△Tf for BaCl2=3×22=3∴ Freezing point of BaCl2=−3∘C

$0.01 M$ solution of $K C l$ and $B a C l_{2}$ are prepared in water. The freezing point of $K C l$ is found to be $- 2^{\circ} C$ . What is the freezing point of $B a C l_{2}$ to be completely ionised?