Question

$0.01mole$ of iodoform $\left(CH{I}_3\right)$ reacts with $Ag$ powder to produce a gas whose volume at $NTP$ is

• A. $224ml$
• B. $112ml$
• C. $336ml$
• D. $448ml$

Answer 1

The correct option is B $112ml$

$2$ moles of iodoform produces one mole of acetylene.
$2CH{I}_3+6Ag\to C_2{H}_2+6AgI$
Hence, $0.01$ mol of iodoform will produce $\frac{1}{2}\times 0.01=0.005$ mol of acetylene.
At NTP, the volume occupied by $0.005$ moles of acetylene is $0.005\times 22.4=0.112$ L or $112$ ml.