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Question

0.01 mole of iodoform (CHI3) reacts with excess Ag powder to produce a gas, whose volume at NTP is:

A
224 ml
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B
112 ml
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C
336 ml
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D
448 ml
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Solution

The correct option is B 112 ml
The reaction would be 2CHI3+6Ag6AgI+C2H2

2 moles CHI3 produce 1 mole ethylene gas.

0.01 mole will produce =0.012=0.005 mole gas

Volume of 0.005 mole gas at NTP =0.005×22.4=0.112 L=112 ml

Volume of gas (C2H2)=112ml

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