Question

$0.01mole$ of iodoform $\left(CH{I}_3\right)$ reacts with excess $Ag$ powder to produce a gas, whose volume at NTP is:

• A. $224ml$
• B. $112ml$
• C. $336ml$
• D. $448ml$

Answer 1

The correct option is B $112ml$

The reaction would be $2CH{I}_3+6Ag\to 6AgI+C_2{H}_2$

$2molesCH{I}_3$ produce $1mole$ ethylene gas.

$0.01mole$ will produce $=\frac{0.01}{2}=0.005mole$ gas

Volume of $0.005$ mole gas at NTP $=0.005\times 22.4=0.112L=112ml$

Volume of gas $\left(C_2{H}_2\right)=112ml$