Question

0.0416 mol of a carbohydrate having an empirical formula $C{H}_{2}O$ contains $1\text{g}$ of hydrogen. The molecular formula of the carbohydrate is:

• A. $C_{12}{H}_{24}{O}_{12}$
• B. $C_6{H}_{12}{O}_6$
• C. $C_{12}{H}_{24}{O}_{11}$
• D. $C_8{H}_{14}{O}_8$

Answer 1

The correct option is A $C_{12}{H}_{24}{O}_{12}$

0.0416 mol of carbohydrate has 1 mol of $H$
So, 1 mol of carbohydrate = $\frac{1\times 1}{0.0416}$ mol of $H$ = 24 mol of $H$
The compound can be either $C_{12}{H}_{24}{O}_{12}$ or $C_{12}{H}_{24}{O}_{11}$
Since the question has provided the empirical formula of the carbohydrate to be $C{H}_{2}O$, option (a) will be the correct answer.