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Question

0.05M NaOH solution offered a resistance of 31.6ohm in a conductivity cell at 298K. If the cell constant of the cell is 0.367cm1, calculate the molar conductivity of the NaOH solution.

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Solution

Given: Molarity of NaOH solution =0.05m
Resistance=31.6ohm
Cell constant=0.367cm1
Now, Molar conductivity=Specific conductivity×1000Molarity
=CellconstantResistance×1000Molarity

=0.367×100031.6×0.05

m=232.3ohm1cm2mol1.

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