Question

$0.05$M NaOH solution offered a resistance of $31.6$ohm in a conductivity cell at $298$K. If the cell constant of the cell is $0.367c{m}^{-1}$, calculate the molar conductivity of the NaOH solution.

Answer 1

Given: Molarity of NaOH solution $=0.05$m
Resistance$=31.6$ohm
Cell constant$=0.367c{m}^{-1}$
Now, Molar conductivity$=\frac{\text{Specific conductivity}\times 1000}{Molarity}$
$=\frac{Cellconstant}{Resistance}\times \frac{1000}{Molarity}$

$=\frac{0.367\times 1000}{31.6\times 0.05}$

${\wedge }_m=232.3oh{m}^{-1}c{m}^{2}mo{l}^{-1}$.