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Valency and Oxidation State

0.1 g of meta...

Question

0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is :

A

12

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B

24

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C

6

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D

36

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Solution

The correct option is A 12
$1$ mol of $O_{2} = 4$ eq. of O
$22400$ mL of $O_{2} = 4$ eq. of O
$46.6$ mL of $O_{2} = \frac{4}{22400} \times 46.6$ $= 0.00832$ eq.
Equivalent of metal $=$ Equivalent of O
$\frac{W e i g h t}{E} = 0.00832$
$\frac{0.1}{E} = 0.00832$
$∴ E = \frac{0.1}{0.00832} = 12.0$

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