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Arrhenius Acid

0.1 M HCl and...

Question

$0.1 M H C l$ and $0.2 M H_{2} S O_{4}$ solutions are mixed in equal volume. This solution is diluted to double the volume. $20 m l$ of this diluted solution can neturalise $x m l$ of $0.1 M N a O H$ solution. Find $x$ :

A

20 m l

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B

40 m l

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C

50 m l

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D

25 m l

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Solution

The correct option is A $25 m l$
$0.1$ $N$ $H C l$ , $0.4$ $N$ $H_{2} S O_{4}$

$N_{t} = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}} = \frac{0.1 \times V + 0.4 \times V}{V + V} = 0.25$

Volume is doubled $\to$ Concentration is halved.

Now, $N_{1} V_{1} = N_{2} V_{2}$

$0.125 \times 20 = x \times 0.1$

$x = 25$ $m L$

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