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Question

# 0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions acccording to equation 5I−+IO−3+6H+→3I2+3H2O which of the following statement is correct?

A
400 ml of the KI solution react with 0.004 mole KIO3
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B
400 ml of the KI solution react with 0.006 mole H2SO4
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C
0.5 litre of the KI solution produced 0.005 mole of I2
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D
Equivalent weight of KIO3 is eual to(Molecular Weight5)
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Solution

## The correct option is D Equivalent weight of KIO3 is eual to(Molecular Weight5)5I−+IO−3+6H+→3I2+3H2O as we know by this equation that 5 moles of KI react with 1 mole ofKIO3 so moles of KI usedMoles of KIO3=5 (A) as we know M=n×1000Volume of solution(in mL) mole(n) of KI=0.1×4001000=0.04 mole(n) ofKIO3=0.045=0.008 (C) mole(n) of KI=0.1×5001000=0.05 mole(n) of KIO3=0.055=0.01 valancy factor of KIO3=5 ∴ Equivalent weight of KIO3=molecular weight of KIO35

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