The correct options are
B 100 ml of the KI solution reacts with 0.006 mol of H2SO4
D Equivalent weight of KIO3 is equal to (Molecularweight5)
The balanced chemical reaction is 5I−+IO−3+6H+→3I2+3H2O.
200 ml of 0.1M KI solution corresponds to 0.2 moles.
MolesofKIusedMolesofKIO3=5
Hence, 200 ml of 0.1M KI solution reacts with 0.004 mol KIO3.
100 ml of 0.1M KI solution corresponds to 0.1 moles.
MolesofKIusedMolesofKIO3=35.
Hence, 100 ml of the KI solution reacts with 0.006 mol of H2SO4.
The valency factor for KIO3=5.
Hence, EKIO3=MolecularweightValencyfactor=Molecularweight5.