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Question

# 0.1M solution of KI reacts with excess of H2SO4 and KIO3 solutions according to equation: 5I−+IO−3+6H→3I2+3H2O Which of the following statement is correct?

A
200 ml of the KI solution reacts with 0.004 mol KIO3
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B
100 ml of the KI solution reacts with 0.006 mol of H2SO4
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C
0.5 litres of the KI solution produced 0.005 mol of I2
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D
Equivalent weight of KIO3 is equal to (Molecularweight5)
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Solution

## The correct options are B 100 ml of the KI solution reacts with 0.006 mol of H2SO4 D Equivalent weight of KIO3 is equal to (Molecularweight5)The balanced chemical reaction is 5I−+IO−3+6H+→3I2+3H2O.200 ml of 0.1M KI solution corresponds to 0.2 moles.MolesofKIusedMolesofKIO3=5Hence, 200 ml of 0.1M KI solution reacts with 0.004 mol KIO3.100 ml of 0.1M KI solution corresponds to 0.1 moles.MolesofKIusedMolesofKIO3=35.Hence, 100 ml of the KI solution reacts with 0.006 mol of H2SO4.The valency factor for KIO3=5.Hence, EKIO3=MolecularweightValencyfactor=Molecularweight5.

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