Question

$0.16$ g of an organic substance was heated in carius tube and sulphuric acid formed was perecipitated as $BaS{o}_4$ and $BaC{l}_2$. The weight of the dry $BaS{O}_4$ was $0.35$ g. Find the percentage of sulphur.

• A. $20$
• B. $30$
• C. $40$
• D. $50$

Answer 1

The correct option is B $30$

Mass of organic compound = 0.16 g

Mass of = 0.35 g

Molar mass of = 233 g/mole

Molar mass of sulfur = 32 g/mole

First we have to calculate the mass of sulfur.

As, 233 g of contains = 32 g of sulfur

So, 0.35 g of contains = of sulfur

Now we have to calculate the percentage of sulfur in organic compound.