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Heat Capacity

0.2 g of an o...

Question

0.2 g of an organic compound contains $C, H, O$ on combustion, it yields 0.15 g of $C O_{2}$ and 0.12 g $H_{2} O$ . The percentage of $C, H$ and $O$ respectively is:

C = 15

H = 20

O = 65

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C = 10

H = 8.2

O = 81.8

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C = 12.2

H = 8.8

O = 79

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C = 20

H = 6.66

O = 73.34

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Solution

The correct option is B $C = 20$ %, $H = 6.66$ %, $O = 73.34$ %
Weight of organic compound = 0.2g
Weight of $C O_{2}$ = 0.15g
Weight of $H_{2} O$ = 0.12g
Molecular weight of $C O_{2}$ = 44
Molecular weight of $H_{2} O$ = 18
Atomic weight of carbon = 12u
Atomic weight of $H_{2}$ = 2u
$Percentage of carbon = \frac{Atomic weight of carbon}{Molecular weight of C O_{2}} \times \frac{Weight of C O_{2}}{W e i g h t o f o r g a n i c c o m p o u n d} \times 100$
$Percentage of carbon = \frac{12}{44} \times \frac{0.15}{0.2} \times 100 = 20.45 % \approx 20 %$
$Percentage of Hydrogen = \frac{Atomic weight of Hydrogen}{Molecular weight of H_{2} O} \times \frac{Weight of H_{2} O}{W e i g h t o f o r g a n i c c o m p o u n d} \times 100$
$Percentage of Hydrogen = \frac{2}{18} \times \frac{0.12}{0.2} \times 100 = 6.66 %$
Percentage of oxygen = 100 - (Percentage of carbon + Percentage of hydrogen) = 100 - (20 + 6.66) = 100 - 26.66 = 73.34 $%$

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0.2 g of an organic compound contains C, H, O on combustion, it yields 0.15 g of CO2 and 0.12 g H2O. The percentage of C, H and O respectively is:

0.2 g of an organic compound contains $C, H, O$ on combustion, it yields 0.15 g of $C O_{2}$ and 0.12 g $H_{2} O$ . The percentage of $C, H$ and $O$ respectively is: