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Question

Calculate the enthalpy of formation of ΔHf for C2H5OH from tabulated data and its heat of combustion as represented by the following equations:
H2(g)+1/2O2(g)H2O(g);ΔHo=241.8kJmol1...(i)
C(s)+O2(g)CO2(g);ΔHo=393.5kJmol1...(ii)
C2H5OH(l)+3O2(g)3H2O(g)+2CO2(g);ΔHo=1234.7kJ...(iii)

A
2747.1kJmol1
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B
277.7kJmol1
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C
277.7.kJmol1
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D
2747.1kJmol1
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Solution

The correct option is B 277.7kJmol1
Required equation
H2(g)+1/2O2(g)C2H5OH(l)
2C(s)+2O2(g)2CO2(g);ΔHo=2×393.5kJmol1
3H2(g)+1/32(g)3H2O(g);ΔHo=3×241.8kJmol1
2H2O(l)+2CO2(g)C2H5OH(l)+3O2(g);ΔHo=+1234.7kJ
On adding
2C(s)+3H2(g)+12O2(g)C2H5OH(l);ΔHo=277.7kJmol1.

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