Heat of Formation
Trending Questions
Q. The value of standard enthalpy of formation of SF6(g), S(g) and F(g)are−1100, 275, 80 kJ/mol respectively. The average bond energy of SF6 (in kJ/mol) is
(Give your answer to the nearest answer)
(Give your answer to the nearest answer)
Q.
The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25∘C are −400 kJ/mol, −300 kJ/mol and −1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25∘C is
+ 2900 kJ
−2900 kJ
−16.11 kJ
+16.11 kJ
Q. Standard molar enthalpy of formation of CO2 is equal to
- Zero
- The standard molar enthalpy of combustion of gaseous carbon
- The sum of standard molar enthalpies of formation of CO and O2
- The standard molar enthalpy of combustion of carbon (graphite)
Q. From the following reactions, heat of formation of SO2(g) is
S(g)+32O2(g)→SO3(g)+2x kcal
SO2(g)+12O2(g)→SO3(g)+y kcal
S(g)+32O2(g)→SO3(g)+2x kcal
SO2(g)+12O2(g)→SO3(g)+y kcal
- x + y
- 2x + y
- x - y
- 2x - y
Q. The species which by definition has ZERO standard molar enthalpy of formation at 298 K is
Br2(g)
Cl2(g)
H2O(g)
CH4(g)
Q. The standard heat of formation of diamond is
- Less than that of graphite
- Zero
- Same as that of graphite
- Greater than that of graphite
Q. For which of the following reactions ΔHreaction is equal to ΔHformation
Q. Calculate the heat of formation of acetic acid from the following data.
CH3COOH(l) + 2O2(g) →2CO2(g) + 2H2O(l), △H= −207.9 K cal
C(s) + O2(g)→CO2(g) △H = −94.48 K cal
H2(g) + 12O2(g)→H2O(l) △ H = −68.4 K cal
CH3COOH(l) + 2O2(g) →2CO2(g) + 2H2O(l), △H= −207.9 K cal
C(s) + O2(g)→CO2(g) △H = −94.48 K cal
H2(g) + 12O2(g)→H2O(l) △ H = −68.4 K cal
117.86 K cal
-117.86 K cal
116.86 K cal
-116.86 K cal
Q. The enthalpy of formation of two compounds A and B are -84 kJ/mol and -156 kJ/mol respectively. Which of the following statements about A and B are correct?
- A is less stable than B
- Both A and B are unstable
- Both A and B are endothermic compounds
- A is more stable than B
Q. Which of the following equations correctly represents the standard heat of formation of methane
- C(graphite)+2H2(g)=CH4(l)
- C(graphite)+2H2(g)=CH4(g)
- C(graphite)+4H=CH4(g)
- C(diamond)+2H2(g)=CH4(g)