Question

Question 10
$0.25(4f-3)=0.05(10f-9)$

Answer 1

$0.25(4f-3)=0.05(10f-9)\Rightarrow 1.00f-0.75=0.50f-0.45$
$\Rightarrow 1.00f-0.50f=-0.45+0.75\Rightarrow 0.50f=0.3$
$\Rightarrow f=\frac{0.3}{0.50}\Rightarrow f=0.6$
To check :
$0.25(4f-3)=0.05(10f-9)\Rightarrow 0.25(4\times 0.6-3)=0.05(10\times 0.6-9)$
$\Rightarrow 0.25(2.4-3)=0.05(6.0-9)\Rightarrow 0.25\times (-0.6)=0.05\times (-3)$
$\Rightarrow -0.150=-0.150$
$\Rightarrow L.H.S=R.H.S$
Therefore, it is correct.