Question

0.25g of an organic compound gave 31.1ml of $N_2$ at STP. The % of N in the organic compound is:

• A. 15.55
• B. 16.23
• C. 10.41
• D. 18.23

Answer 1

The correct option is A 15.55

% of $N=\frac{28}{22400}\times \frac{Valof{N}_{2}atSTP}{Massofcompd}\times 100$
( As we know that at STP the volume of the gas is 22400ml)
= $\frac{28}{22400}\times \frac{31.1}{0.25}\times 100$
=$\frac{3.8875}{0.25}=15.55$
% $N=15.55$