Question

$0.32$ g of an organic compound containing sulphur produces $0.233$ g of $BaS{O}_4$. Percentage of sulphur in the compound is:

• A. $20$
• B. $50$
• C. $10$
• D. $80$

Answer 1

Answer: (C)

$10$

Molar mass of $BaS{O}_4=233g$

Let the mass of $BaS{O}_4$ formed$=0.233g$

we know that,

$32g$ of Sulphur is present in $1$ mol. of $BaS{O}_4$

$\therefore 233gBaS{O}_4$ contains $32g$ sulphur.

$\Rightarrow 0.233gofBaS{O}_4$ contains $\frac{32\times 0.233g}{233}$ of sulphur

$\%$ of sulphur$=\frac{32\times 0.233\times 100}{233\times 0.32}$

$=\frac{745.6}{74.56}$

$=10\%$

Hence, correct option is $c$