Question

2.18 g of an organic compound containing sulphur produces 1.02 g of $BaS{O}_4$. the percentage of sulphur in the compound is:

• A. 7.26%
• B. 8.98%
• C. 10%
• D. 6.42%

Answer 1

Answer: (D)

6.42%

Mass of Sulphur = 32u

Mass of $BaS{O}_4$ = 233u

Weight of $BaS{O}_4$ = 1.02g

Weight of organic compound = 2.18g

$\text{Percentage of sulphur}=\frac{\text{Mass of Sulphur}}{\text{Mass of}BaS{O}_4}\times \frac{\text{Weight of}BaS{O}_4}{\text{Weight of organic compound}}\times 100$

$\text{Percentage of Sulphur}=\frac{32}{233}\times \frac{1.02}{2.18}\times 100=6.42\%$

Hence, option $D$ is correct answer.