Question

$0.23$ g of an organic compound gave $0.332$ g of $BaS{O}_4$ . Determine the % of sulphur in the compound.

• A. $32.61$%
• B. $8.5$%
• C. $19.77$%
• D. None of these

Answer 1

The correct option is C $19.77$%

Molar mass of $BaS{O}_4$ = 233 g

Suppose the mass of organic compound = m grams

Let the mass of barium sulphate formed = 0.332 grams

We know that 32 grams of sulphur are present in 1 mol of $BaS{O}_4$

Therefore, 233 g $BaS{O}_4$ contains 32 g sulphur

⇒ 0.332 g of $BaS{O}_4$ contains $(32\times 0.332)233$ grams of sulphur

Percentage of sulphur = $\frac{32\times 0.332\times 100}{233\times 0.23}$ = 19.77%

CORRECT ANSWER IS (C)