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Nitrogen

0.365 g of an...

Question

0.365 g of an organic compound containing nitrogen gives 56 ml of nitrogen at S.T.P. The percentage of nitrogen in the given compound is (as nearest integer)

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Solution

Moles of nitrogen $= 56 / 22400$
mass of nitrogen in sample $= 28 * 56 / 22400 = 0.07 g m$
so % of N $= 0.07 * 100 / 0.365 = 19.18$
Nearest integer is 19.

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