Question

$0.365$ gm of an organic compound containing nitrogen gives $56$ ml of nitrogen at STP. The percentage of nitrogen in the given compound is:

• A. $19.18\%$
• B. $38.36\%$
• C. $9.18\%$
• D. $29.18\%$

Answer 1

The correct option is A $19.18\%$

Volume of nitrogen gas obtained $=$ 56 ml
So, moles of nitrogen gas $=\frac{56}{22400}$ (As volume of one mole of gas is 22400 ml)

Mass of nitrogen gas evolved is $=\frac{56}{22400}\times 28=0.07$ gm

So, the organic compound contains 0.07 gm of nitrogen,

$\%$ of nitrogen in the compound $=\frac{0.07}{0.365}\times 100=19.18\%$

Option A is correct.