Question

$0.4$g of an organic compound gave $0.188$g of silver bromide by a halogen estimation method. The percentage of bromine in the compound is:(Atomic mass of Ag $=$ 108, Br$=$ 80)

• A. 39.8%
• B. 40.0%
• C. 20%
• D. 48%

Answer 1

The correct option is C 20%

Percentage of $Br=\frac{80}{188}\times \frac{MassofAgBr\times 100}{Massofcompound}$

$=\frac{80}{188}\times \frac{0.188\times 100}{0.4}=\frac{8}{0.4}$ $=20\%$