$0.4 g m$ of an organic compound gave $0.188 g$ of silver bromide by a halogen estimation method. The percentage of bromine in the compound is:

[At.mass of $A g = 108$ and $B r = 80$ ]

39.8

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46 / 0

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20.0

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40.0

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Solution

The correct option is C $20.0$ %
Mass of halogen in $0.4 g$ of compound,

$= \frac{80}{188} \times 0.188 = 0.08 g$

% $B r = \frac{0.08}{0.4} \times 100 = 20$ %

Hence, option C is correct.

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0.4

g of an organic compound gave

0.188

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=

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Q. In Carius method of estimation of halogen 0.15 gram of an organic compound gave 0.12 gram of AgBr . calculate % of bromine in the compound. (Ag=108, Br=80)

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is (At. Mass Ag = 108; Br = 80)

Q. In the estimation of halogen,

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0.4 gm of an organic compound gave 0.188 g of silver bromide by a halogen estimation method. The percentage of bromine in the compound is:[At.mass of Ag=108 and Br=80]

The correct option is C 20.0%Mass of halogen in 0.4g of compound,=80188×0.188=0.08g% Br=0.080.4×100=20%Hence, option C is correct.

$0.4 g m$ of an organic compound gave $0.188 g$ of silver bromide by a halogen estimation method. The percentage of bromine in the compound is:

[At.mass of $A g = 108$ and $B r = 80$ ]

The correct option is C $20.0$ %
Mass of halogen in $0.4 g$ of compound,

$= \frac{80}{188} \times 0.188 = 0.08 g$

% $B r = \frac{0.08}{0.4} \times 100 = 20$ %

Hence, option C is correct.