$0.44 g$ of a hydrocarbon on complete combustion with oxygen gave $1.8 g$ water and $0.88 g$ carbon dioxide. Show that these results are in accordance with the law of conservation of mass.

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Solution

A hydrocarbon is a compound which consists of carbon and hydrogen only. It undergoes combustion forming carbon dioxide and water as products.
Formula of carbon dioxide $= C O_{2}$ ;
Molecular mass $= 12 + 32 = 44 g$
Formula of water $= H_{2} O$ ;
Molecular mass $= 2 + 16 = 18 g$
Mass of carbon in 0.88 g of $C O_{2} \frac{12}{44} \times 0.88 = 0.24 g$
Mass of hydrogen in 1.8 g of $H_{2} O = \frac{2}{! 8} \times 1.8 = 0.20 g$
Total masses of carbon and hydrogen in the products $= 0.24 + 0.20 = 0.44 g$
This is equal to the mass of hydrocarbon before combustion. Thus, the results are in accordance with the law of conservation of mass.

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0.44g of a hydrocarbon on complete combustion with oxygen gave 1.8g water and 0.88g carbon dioxide. Show that these results are in accordance with the law of conservation of mass.

$0.44 g$ of a hydrocarbon on complete combustion with oxygen gave $1.8 g$ water and $0.88 g$ carbon dioxide. Show that these results are in accordance with the law of conservation of mass.