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Percentage Composition

0.5 g of an o...

Question

$0.5$ g of an organic compound on combustion produced some gaseous products which were passed into caustic potash solution. The increase in weight of potash solution was found to be $1.5$ g. The percentage of carbon in the compound is nearly:

A

82

%

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B

40

%

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C

60

%

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D

75

%

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Solution

The correct option is A $82$ %
Since $K O H$ is a solvent for $C O_{2}$ ,

weight of $C O_{2}$ evolved is $1.5$ g $= \frac{1.5}{44} = 0.034$ mol.

$1$ mole of $C O_{2}$ contains $12$ g of $C$ .

$∴ 0.034$ moles will contain $12 \times 0.034 = 0.408$ g of $C$ .

Percentage of $C$ in the compound is $\frac{0.408}{0.5} \times 100 = 81.6$ %.

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