Question

$0.5M{H}_{2}S{O}_4$ is diluted from 1 litre to 10 litres, normality of the resulting solution is:

• A. 1 N
• B. 0.1 N
• C. 10 N
• D. 11 N

Answer 1

Answer: (B)

0.1 N

Normality $=$ Molarity $\times$ Valency factor of $H_{2}S{O}_4$

$=0.5\times 2N$

Normality $=1N$

Now,

$N_1{V}_1=N_2{V}_2$

$\Rightarrow 1\times 1L=N_2\times 10L$

$\Rightarrow N_2=0.1N$

Hence, the correct option is $B.$