$0.56$ g of gas occupies $280$ $c m^{3}$ at NTP. Then its molecular mass is:

4.8

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44.8

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11.2

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22.4

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Solution

The correct option is D 44.8
At NTP, $280$ cc or $0.28$ L weigh $0.56$ g of a gas.

Since we know that, 22.4 L corresponds to 1 mole of a gas at NTP.

$22.4$ L will weigh to $\frac{0.56}{0.28} \times 22.4 = 44.8 g$ .

Hence, option B is correct.

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