1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Half life
0.5952 g of a...
Question
0.5952
g of an organic substance, when treated by Carius method, gave
0.52
g of
B
a
S
O
4
. Calculate the % of the compound.
A
23.16
%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23.35
%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
11.96
%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
11.96
%
Percentage of sulphur in the compound
=
32
233
×
m
a
s
s
o
f
B
a
S
O
4
m
a
s
s
o
f
c
o
m
p
o
u
n
d
×
100
32
×
0.52
×
100
233
×
0.5952
=
11.96
C is answer
Suggest Corrections
0
Similar questions
Q.
0.2595
g of an organic substance, when treated by carius method, gave
0.25
g of
B
a
S
O
4
. Calculate the percentage of sulphur in the compound.
Q.
0.53
g of substance gave
1.158
g of
B
a
S
O
4
by Carius method. Calculate the percentage of sulphur.
Q.
A
0.2595
g of an organic compound by Carius method gave
0.350
g of barium sulphate. Calculate the percentage of sulphur in the compound.
Q.
0.40
g of an iodo substituted organic compound by Carius method gave
0.235
g of silver iodide. Calculate the percentage of iodine in the compound.
Q.
In an estimation of sulphur by Carius method
0.2175
g of the substance gave
0.5825
g of barium sulphate. Calculate then percentage of sulphur in the compound.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Half Life
CHEMISTRY
Watch in App
Explore more
Half life
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app