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Ideal Gas Equation

0.6 g of a sa...

Question

$0.6 g$ of a sample containing $B e C_{2} O_{4} .3 H_{2} O$ $a n d s o m e i n e r t i m p u r i t y i s d i s s o l v e d i n$ 100\ ml $w a t e r . A$ 20\ ml $p o r t i o n o f t h i s s o l u t i o n r e q u i r e d$ 17.8\ ml $o f$ 0.015\ M $a c i d i f i e d$ KMnO_4 $s o l u t i o n t o r e a c h t h e e q u i v a l e n c e p o i n t . I f t h e m a s s$ \% $o f$ BeC_2O_4.3H_2O $i n t h e o r i g i n a l s a m p l e i s$ 12\ x\% $. t h e n v a l u e o f$ 'x'$ is .............

A

74 %

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B

56 %

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C

84 %

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D

97 %

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Solution

The correct option is D $84 %$
Total meqvt. of $C_{2} O_{4}^{2 -} = 17.8 \times 0.015 \times 5 \times 5 = 6, 675$
Mass of $B e C_{2} O_{4} .3 H_{2} O = \frac{6.675}{2} \times \frac{151}{1000} = 0.504 g$
$∴$ Mass % $= \frac{0.504}{0.60} \times 100 = 84$ %

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