Question

0.64 g of a gas occupies a volume of 224 ml at STP. The gas could be

• A. $N_{2}O$
• B. $O_2$
• C. $S{O}_3$
• D. $S{O}_2$

Answer 1

The correct option is D

$S{O}_2$

1 mole of a gas at STP = 22400L of volume
Number of moles of a gas = Given Mass/molar mass
Molar mass of gas $=\frac{0.64\times 22400}{224}=64g$; hence $S{O}_2$