0,59 of an oxalate was dissolved in water and the solution made to 100ml. On tritation 10ml of this solution required 15ml of N20KMnO4. Calculate the percentage of oxalate in the sample.
A
66.0
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B
663
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C
0.66
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D
33.33
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Solution
The correct option is C66.0 0.5g oxalate (impure) in 100ml