1.0 g of $C a C O_{3}$ on decomposition produces 0.56 g of CaO and the rest is $C O_{2}$ . The volume of $C O_{2}$ evolved at STP is,

0.227 mL

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227 mL

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22.7 mL

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2.27 mL

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Solution

The correct option is B 227 mL
$C a C O_{3} \to C a O + C O_{2}$
1mol 1mol 1mol
100gm $C a C O_{3}$ = 1mol
1gm $C a C O_{3} = \frac{1}{100}$ mol = 0.01 mol
1mol of $C a C O_{3}$ produces 1 mol $C O_{2}$
0.01 mol of $C a C O_{3}$ produces = 0.01 mol
1mol $C O_{2}$ contains 22.7 litres $C O_{2}$ at STP
0.01 mol $C O_{2}$ contains 0.227 litres $C O_{2}$ at STP = 227 ml.

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