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Standard XII

Chemistry

Types of Redox Reactions

The volume of...

Question

The volume of $C O_{2}$ produced at STP by decomposition of $4.2$ g of $N a H C O_{3}$ according to the reaction:
$2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}$

150

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569

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1.68

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5.6

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Solution

The correct option is C $569$ ml
$2 N a H C O_{3} ⟶ N a_{2} C O_{3} + H_{2} O + C O_{2}$
$\Rightarrow 2 \times 84 g ⟶$ litres of $C O_{2}$
$\Rightarrow 4.29 g ⟶ ? (x)$
$\Rightarrow x = \frac{4.29 \times 22.4}{2 \times 84} = 0.569 l i t r e s$
$\Rightarrow x = 569 m l$

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Similar questions

Q. Three mol of

N a_{2} C O_{3}

is allowed to react with a solution containing 6 mol of

H C l

. Find the volume of

C O_{2}

gas (in L) produced at STP.

N a_{2} C O_{3} + 2 H C l ⟶ 2 N a C l + C O_{2} + H_{2} O

Q. The volume of

C O_{2}

obtained by the complete decomposition of 9.8 g

N a_{2} C O_{3}

S T P

is :

Q. 6 moles of

N a_{2} C O_{3}

is reacted with 10 moles of

H C l

. Find the volume of

C O_{2}

gas produced at STP.
The reaction is:

N a_{2} C O_{3} + 2 H C l \to 2 N a C l + C O_{2} + H_{2} O

Q. What weight of

C a C O_{3}

must be decomposed to produce a sufficient quantity of carbon dioxide to convert

21.2 g

N a_{2} C O_{3}

completely into

N a H C O_{3}

. (Molar mass of

N a = 23 g/mol, C a = 40 g/mol

C a C O_{3} \to C a O + C O_{2}

N a_{2} C O_{3} + C O_{2} + H_{2} O \to 2 N a H C O_{3}

6.2

g of a sample containing

N a_{2} C O_{3}, N a H C O_{3}

amd non-volatile inert impurity on heating loses

5 %

of its weight due to formation of

H_{2} O

and

C O_{2}

as in reaction:

2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}

Residue is dissolved in water and formed

100

ml solution and its

10

ml portion requires

4.5

ml of

0.2 M

aqueous solution of

B a C l_{2}

for complete precipitation of carbonates. If number of moles of

N a_{2} C O_{3}

in the original sample were

q

, then the value of

100 q

is:

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The volume of CO2 produced at STP by decomposition of 4.2g of NaHCO3 according to the reaction:2NaHCO3→Na2CO3+H2O+CO2

The correct option is C 569ml2NaHCO3⟶Na2CO3+H2O+CO2⇒2×84g⟶ litres of CO2⇒4.29g⟶?(x)⇒x=4.29×22.42×84=0.569litres⇒x=569ml

The volume of $C O_{2}$ produced at STP by decomposition of $4.2$ g of $N a H C O_{3}$ according to the reaction:
$2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}$

The correct option is C $569$ ml
$2 N a H C O_{3} ⟶ N a_{2} C O_{3} + H_{2} O + C O_{2}$
$\Rightarrow 2 \times 84 g ⟶$ litres of $C O_{2}$
$\Rightarrow 4.29 g ⟶ ? (x)$
$\Rightarrow x = \frac{4.29 \times 22.4}{2 \times 84} = 0.569 l i t r e s$
$\Rightarrow x = 569 m l$