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Question

What weight of CaCO3 must be decomposed to produce a sufficient quantity of carbon dioxide to convert 21.2 g of Na2CO3 completely into NaHCO3. (Molar mass of Na=23 g/mol,Ca=40 g/mol): CaCO3→CaO+CO2 Na2CO3+CO2+H2O→2NaHCO3

A
100 g
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B
20 g
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C
120 g
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D
30 g
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Solution

The correct option is B 20 gCaCO3→CaO+CO2 Na2CO3+CO2+H2O→2NaHCO3 Mol of Na2CO3=21.2106=0.2 mol 1 mol of Na2CO3 reacts with 1 mol of CO2 and 1 mol of CO2 is produced from 1 mol of CaCO3 i.e. mol of Na2CO3= mol of CO2=mol of CaCO3 So, 0.2 mol of Na2CO3 reacts with 0.2 mol of CO2 which means 0.2 mol of CO2 is produced from 0.2 mol of CaCO3. weight of CaCO3 formed = Moles × Molar mass hence, weight of CaCO3=0.2 mol×100 g/mol=20 g

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