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pH of a Solution

1.0 L solutio...

Question

$1.0 L$ solution is prepared by mixing $61 g m$ benzonic acid $(p K_{a} = 4.2)$ with $72 g m$ of sodium benzoate and then $300 mL 1.0 M HBr$ solution was added. the $p H$ of final solution is:-

3.6

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3.8

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4.2

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4.8

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Solution

The correct option is C $3.6$
Mol of $C_{6} H_{5} C O O H = \frac{61}{122} = 0.5;$
Mol of $C_{6} H_{5} C O O N a = \frac{72}{144} = 0.5;$
$p H = p K_{a} + l o g \frac{(C_{6} H_{5} C O O N a)}{(C_{6} H_{5} C O O H)}$
$p H = 4.2 + l o g \frac{0.2}{0.8} = 3.6$

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