$(1.02)^{2} - (0.98)^{2} =$

0.6

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0.8

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0.06

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0.08

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Solution

The correct option is D
0.08

Using the identity,
$a^{2} - b^{2} = (a + b) (a - b)$

$(1.02)^{2} - (0.98)^{2}$ $= (1.02 + 0.98) (1.02 - 0.98)$
$= 2 \times 0.04 = 0.08$

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Similar questions

$(1.02)^{2} - (0.98)^{2} =$

(1.02)^{2} - (0.98)^{2}

(1.02)^{2} - (0.98)^{2}

Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
${1.02}^{2} - {0.98}^{2}$

Using the identity a^{2} - b^{2} = (a + b) (a - b)

Find the value of (1.02)^{2} - (0.98)^{2} .

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