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Question

12+22+32+42+...+72= .

A
120
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B
140
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C
105
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Solution

The correct option is B 140
The sum of the squares of the first n natural numbers is given by
Sn=12+22+32+...+n2
=n(n+1)(2n+1)6.

Here, n=7.
S7=12+22+32+42+...+72
=7(7+1)(2×7+1)6
=7×8×156
=140
Thus, 12+22+32+42+...+72=140.



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