Question

1 2
$N\equiv C-CH={CH}_2$

What is the hybridization of carbons marked as 1 and 2?

• A. ${sp}^{2}and{sp}^2$
• B. ${sp}^{3}andsp$
• C. $spand{sp}^2$
• D. $spandsp$

Answer 1

Answer: (A)

${sp}^{2}and{sp}^2$

The two carbons marked are bonded by double bond.

No other triple bonds are attached to them. Double bonded Carbon atoms have $s{p}^2$ hybridisation. So, the ${}^{\prime }{C}^{\prime }$ atoms have $s{p}^2$ and $s{p}^2$ hybridisation.