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Question

1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of CO2 and 2.7 g of H2O, then the data illustrates:

A
Law of conservation of mass
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B
Law of multiple proportions
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C
Law of constant composition
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D
Law of reciprocal proportions
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Solution

The correct option is A Law of conservation of mass
Explanation:
Mass of hydrocarbon CxHy=1.5g

C changes to CO2 and H changes to H2O

C in 4.4g CO2 is 1.2g (in 44g --- CO2 12g of Carbon is present, so in 4.4g 1.2g carbon is present)

Hydrogen in 2.7g H2O=2×2.718=0.3g

Mass of C+H=1.2+0.3=1.5g

Which is equal to the mass of hydrocarbon taken.

So this is law of conservation of mass, because here mass is conserved.

Hence option A is correct.

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