1.52 g of the silver salt of an organic acid (M.M = 90 g/mol) when ignited, gives 1.08 g of pure silver. The basicity of the acid will be:
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is B 2 Let the balanced chemical equation be,
HnA→AgnA→nAg Mass of the silver salt = 1.52 g Mass of the Ag residue = 1.08 g Molar mass of (Organic acid) = 90 g/mol Molar mass of (Salt) = 90 - n + 108 n = 90 + 107 n g/mol where n is the replaceable H or basicity of the acid Hence moles of the silver salt = 1.5290+107n moles of Ag =1.08108 applying POAc on Ag (1.5290+107n)×n=1.08108 n = 2