Question

$1.520g$ of metal hydroxide on ignition gave $0.995g$ of oxide. What is the equivalent unit of metal?

Answer 1

One eq. of metal reacts with $1$ mole of $OH=17$g. & $1$ eq. of metal reacts with $1/2$ mole of $o$ atoms $=8g$ of $O$ atoms.

Let $E$ be the eq. mass of metal & $X$ be the no. of equivalents of metal hydroxide ignited.

$\therefore$ $X[E+17]=1.52$ & $X[E+8]=0.995$

$\Rightarrow E=9.06g$