MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Problem Solving

1. A block of...

Question

{ 1. A block of mass }2 kg rests on an inclined plane }}{ of inclination angle }37^° , then calculate the force of }}{ friction acting on the block [take } g = 10 m / s ^ { 2 } \rbrack

Open in App

Solution

Suggest Corrections

thumbs-up

6

Similar questions

Q. A block of mass

2 k g

rests on an inclined plane of inclination angle

37^{o}

, then calculate the force of friction acting on the block (take

g = 10 m / s^{2}

Q. A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2 m/

s^{2}

. Kinetic friction force acting on block is (take g = 10 m/

s^{2}

)

Q. A block rests on a rough inclined plane making an angle

30^{0}

with horizontal. The coefficient of static friction between the block and inclined plane is

0.8

. If the maximum frictional force on the block is

10 N

, the mass of the block in

k g

g = 10 m / s^{2}

Q. A block rests on a rough inclined plane making an angle of

30^{\circ}

with horizontal. The coefficient of static friction between the block and inclined plane is 0.8. If the frictional force on the block is 10N, the mass of the block in kg is (g=10

m / s^{2}

)

Q. A block rests on a rough inclined plane making an angle of

30^{\circ}

with the horizontal. The coefficient of static friction between the block and the plane is

0.8

. If the frictional force on the block is

10 N

, the mass of the block (in

kg

g = 10 {m/s}^{2}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

PHYSICS

Watch in App

explore_more_icon

Explore more

Problem Solving

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon