1−ButynehotKMnO4−−−−−−−→X+Y Identify X and Y?
A
CH3CH2CH3COCH+O2
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B
CH3COOH
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C
CH3CH2COOH+CO2+H2O
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D
CH3CH2COCH+HCOOH
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Solution
The correct option is BCH3CH2COOH+CO2+H2O option C must be the right answer. Terminal Alkynes like 1-butyne in the presence of KMnO4 under basic conditions forms 1-propionic acid and water. CH3CH2C≡CH→CH3CH2COOH+CO2+H2O