1 CGraphite-O2g- CO2g- H-94 K-Cals 2 CDiamond-O2g- CO2g- H-94-5 K-CalsFrom the above data- the heat of transition is-

The correct option is D 500 Cal 1) C_Graphite+O_2(g)→ CO_2(g); H= 94 K.Cals #10; 2) C_Diamond+O_2(g)→ CO_2(g); #10;H= 94.5 K.Cal ...

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1 CGraphite+O...

Question

$1) C_{G r a p h i t e} + O_{2 (g)} \to C O_{2 (g)}; △ H = - 94 K . C a l s$
$2) C_{D i a m o n d} + O_{2 (g)} \to C O_{2 (g)}; △ H = - 94.5 K . C a l s$
From the above data, the heat of transition is:

- 50 C a l

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- 100 C a l

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- 500 C a l

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100 C a l

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C_{(d i a m o n d)} + O_{2} (g) \to C O_{2} (g) △ H = - 94.5 K c a l

C_{(g r a p h i t e)} + O_{2} (g) \to C O_{2} (g) △ H = - 94.0 K c a l

C (s) + O_{2} (g) \to {C O}_{2} (g); Δ H = - 395 k J

S (s) + O_{2} (g) \to {S O}_{2} (g); Δ H = - 295 k J

C S_{2} (l) + 3 O_{2} (g) \to {C O}_{2} (g) + 2 {S O}_{2} (g); Δ H = - 1110 k J

C S_{2} (l)

Δ H_{t}

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g)

Δ H = x k J

C (d i a m o n d) + O_{2} (g) \to C O_{2} (g)

Δ H = y k J

C (d i a m o n d, s) + O_{2} (g) \to C O_{2} (g); △ H = - 94.3 k c a l

C (g r a p h i t e, s) + O_{2} (g) \to C O_{2} (g); △ H = - 97.6 k c a l

C (d i a m o n d, s) \to C (g r a p h i t e, s)

Heat of formation of $C H_{4}$ is:

If given:

$C (s) + O_{2} (g) \to C O_{2} (g) △ H = - 394 k J$

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) △ H = - 284 k J$

$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l) △ H = - 892 k J$

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