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1. C u 2+ +2...

Question

1. $C u^{2 +} + 2 e^{-} ⟶ C u$ , $E^{0} = 0.337 V$
2. $C u^{2 +} + e^{-} ⟶ C u^{+}$ , $E^{0} = 0.153 V$
Electrode potential, $E^{0}$ for the reaction $C u^{+} + e^{-} ⟶ C u$

0.90V

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0.30V

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0.38V

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0.52V

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Solution

The correct option is
D
0.52V
Given,

The required reaction is,
$C u^{+} + e^{-} ⟶ C u; E^{0} = ?$
$Δ G^{o} = Δ G_{1}^{o} + Δ G_{2}^{o}$
$\Rightarrow - n F E_{C u^{2 +} / C u}^{o} = - n F E_{C u^{2 +} / C u^{+}}^{o} + - n F E_{C u^{+} / C u}^{o}$
$\Rightarrow - (2 E_{C u^{2 +} / C u}^{o}) = - E_{C u^{2 +} / C u^{+}}^{o} - E_{C u^{+} / C u}^{o}$
$\Rightarrow - (2 \times 0.337) = - 0.153 - E_{C u^{+} / C u}^{o}$
$\Rightarrow - 0.674 + 0.153 = - E_{C u^{+} / C u}^{o}$
$\Rightarrow + 0.52 = + E_{C u^{+} / C u}^{o}$
$\Rightarrow E_{C u^{+} / C u}^{o} = 0.52 V$

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Similar questions

{C u}^{2 +} + {2 e}^{-} \to C u, E^{o} = + 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+} E^{o} = + 0.153 V

E^{0}

{C u}^{+} + e^{-} \to C u

{C u}^{2 +} + {2 e}^{-} \to C u, E^{\circ} = 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

{C u}^{+} + e^{-} \to C u,

C u^{2 +} + 2 e^{-} \to C u, E^{\circ} = 0.337 V

C u^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

C u^{+} + e^{-} \to C u

C u^{2 +} / C u

C u^{2 +} / C u^{+}

0.337 V

0.153 V

C u^{+} / C u

$C u - 2 e^{-} \to C u^{2 +}, E^{0} = - 0.347 V$

$S n - 2 e^{-} \to S n^{2 +}, E^{0} = + 0.143 V$

The EMF of the cell constructed with these electrodes is :

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