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Question

Given (i) Cu2++2eCu,Eo=+0.337V


(ii) Cu2++eCu+Eo=+0.153V

Electrode potential, E0 for the reaction will be:
Cu++eCu

A
0.38V
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B
0.52V
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C
0.90V
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D
0.30V
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Solution

The correct option is D 0.52V
$ G = nFE
Δ Gcell=GoCu2+/CuGoCu2+/Cu+

nF Ecell=nFEoCu2+/Cu(nFEoCu2+/Cu+)

Eocell=2×EoCu2+/CuEoCu2+/Cu+=2×0.3370.153=0.521

Therefore B is the correct option.

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