$1 \frac{1}{2} + \frac{3}{4} \times \frac{6}{3} \div \frac{1}{4} = . . . . . . . . . . . . .$

2 \frac{1}{2}

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3 \frac{1}{2}

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7 \frac{1}{2}

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8 \frac{1}{2}

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Solution

The correct option is B $7 \frac{1}{2}$
$\frac{3}{2} + \frac{3}{4} \times \frac{6}{3} \div \frac{1}{4} = \frac{3}{2} + \frac{3}{4} \times \frac{24}{3}$
$= \frac{3}{2} + \frac{6}{1} = \frac{3 + 12}{2} = \frac{15}{2} = 7 \frac{1}{2}$

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