1-Chloro-pent-1,3-diene will have X number of geometrical isomers. The the value of X is

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Solution

Number of geometrical isomers = $2^{n}$

Where n = Number of systems showing geometrical isomerism

The systems showing geometrical isomerism can be anything like double bond, ring, biphenyl, cumulene, etc.
$C H_{3} - C H = C H - C H = C H - C l$ Here $n = 2$
$∴ T h e n u m b e r o f g e o m e t r i c a l i s o m e r s = 2^{2} = 4$

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